Arranging 5 Numbers in Ascending Order
code:
//C program for Arranging 5 Numbers in Ascending Order
#include<stdio.h>
#include<conio.h>
void main()
{
int a[5],i,j,t;
clrscr();
printf("Enter 5 nos.\n\n");
for (i=0;i<5;i++)
scanf("%d",&a[i]);
for (i=0;i<5;i++)
{
for(j=i+1;j<5;j++)
{
if(a[i]>a[j])
{
t=a[i];
a[i]=a[j];
a[j]=t;
}
}
}
printf("Ascending Order is:");
for(j=0;j<5;j++)
printf("\n%d",a[j]);
getch();
}
Hope you liked the posts, give comments if you have any doubts.. :)#include<stdio.h>
#include<conio.h>
void main()
{
int a[5],i,j,t;
clrscr();
printf("Enter 5 nos.\n\n");
for (i=0;i<5;i++)
scanf("%d",&a[i]);
for (i=0;i<5;i++)
{
for(j=i+1;j<5;j++)
{
if(a[i]>a[j])
{
t=a[i];
a[i]=a[j];
a[j]=t;
}
}
}
printf("Ascending Order is:");
for(j=0;j<5;j++)
printf("\n%d",a[j]);
getch();
}
13 comments:
thanks, this is really use full for me
thanks a lot...
thank you ,your answer helped me a lot
pls explain for loop...
thnx a lot...realy wrkd!!
thank u...
thanks lot mate....saved my ass frm being fired
thank you it is used for my practical examination
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Thank you this is so useful :)
Thank you! You are great.
thanks... it is our topic in Semi Final Exam :)
NICE IT REALLY WORKED
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